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2 years ago

Which of the following illustrate the commutative property? select all that apply

2 answers:

tatiyna2 years ago

7 0

The answer choices would be: A, D, and E. These would be the correct answer choices because commutative property only works for addition and multiplication. Therefore, C and F are incorrect. B would also be incorrect because it is showing the Distributive Property. I hope this helps!

Sedbober [7]2 years ago

5 0

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Identify the sets of lines to which the given line is a transversal. Line m

Alekssandra [29.7K]

Answer:

Only J and I

Step-by-step explanation:

Transversal Lines are only transversal to sets of parallel lines in which they pass through and P is not parallel to any.

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2 years ago

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Reil [10]

Answer:

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Step-by-step explanation:

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2 years ago

If the half-life of a radioactive substance is 2,800 years, then at what rate is it decaying?

vlada-n [284]

Answer:

0.0001075

Step-by-step explanation:

The relation between halflife and rate at which it is decaying is given by

$t_{\frac{1}{2} } =\dfrac{log2}{rate}$

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3 years ago

The slope of the line in the graph is 4. Fill in the y intercept. Choose the correct equation in the form y = mx + b The y inter

nikitadnepr [17]

Answer:

$\rm\implies y = 4x + 3$

Step-by-step explanation:

Given :-

The slope of the line in the graph is 4.

And we need to find the equation of the line. On looking at the graph we see that , it cuts y axis at (0,3) .So the y Intercept of the equation is 3 .

Slope Intercept Form :-

$\rm\implies y = mx + c$

Substituting the respective values :-

$\rm\implies y = 4*x + 3 \\\\\rm\implies y = 4x + 3$

Hence the equation of line is y = 4x + 3 

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3 years ago

Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the

Alex_Xolod [135]

The speed of both the cars are 80km/h and 60km/h

Step-by-step explanation:

Let the speed of one car be 'a' and the speed of other car be 'b'.

The total distance (d) = 480km

It is given that the speed of one car is 20km/h faster than the other.

We can write,

a = b+20

The slower car takes 2 hrs more to reach the suburb than the other car.

Let the time taken by the fastest car be t

Speed = distance/time

So,

a = 480/ t

b = 480/(t+2)

We got the values of a and b.

a = b+20

480/t = (480/(t+2)) + 20

Taking LCM on the right side.

480/t = (480 + 20t + 40) / (t+2)

480(t+2) = (480+20t+40) t

480t + 960 = 480t + 20t(t) + 40t

20t(t) + 40t - 960 = 0

Divide the whole equation by 20 to simplify the equation.

t(t) + 2t - 48 = 0

Solve the quadratic equation by splitting the middle terms.

t(t) + 8t - 6t - 48 = 0

t(t + 8) - 6(t + 8) = 0

(t- 6) (t+8) =0

t = 6 (or) -8

t is time and cannot be negative. So t= 6hrs

a = 480/t

a = 480/ 6 = 80

the speed of the fastest car is 80km/hr

a = b + 20

b = a - 20

b = 80 - 20

b = 60km/h

4 0

3 years ago