Answer:
u1 = 1
u6 = 31
un = 1 + 6(n - 1)
Step-by-step explanation:
Sn = 3n² - 2n
u1 = S1
3(1)² - 2(1)
3 - 2
1
u6 = S6 - S5
[3(6)² - 2(6)] - [3(5)² - 2(5)]
96 - 65
31
un = a + (n - 1)d
u6 = a + 5d
31 = 1 + 5d
5d = 30
d = 6
un = 1 + 6(n - 1)
Answer:
we can write them as (x^7/2)×(x^5/3)
by laws of exponent :- (x)^7/2+5/3
which is (x)^35/6.
so yeah Kenzie is right.
Use the <u>factor pairs</u> of 36. You'll find that he has
9 different ways to arrange them:
<em>1 x 36</em> ... 1 tulip each in 36 vases, or 36 tulips in1 vase
<em>2 x18</em> ... 2 tulips each in 18 vases, or 18 tulips each in 2 vases
<em>3 x 12</em> ... 3 tulips each in 12 vases, or 12 tulips each in 3 vases
<em>4 x 9</em> ... 4 tulips each in 9 vases, or 9 tulips each in 4 vases
<em>6 x 6</em> ... 6 tulips each in 6 vases
