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pentagon [3]
3 years ago
9

Rob owes Debra $36 and pays her 1/3 of what he owes. How much does he now owe?

Mathematics
2 answers:
wolverine [178]3 years ago
6 0

Answer:

24

Step-by-step explanation:

gregori [183]3 years ago
6 0
He paid $12 dollars he now owes $24

Explanation:
36/3=12
36-12=24
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In an election, 471 people voted. Candidate B received 2/3 of the votes. How many votes did Candidate B receive?
dezoksy [38]

Answer:

Step-by-step explanation:

471/3 * 2 = 314

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3 years ago
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A net force of 66 N accelerates a child at 2.0m/s 2 down a smooth playground slide what is the mass of the child?
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I think it c cause 68
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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
What is the factored form of 27 - 530?
fenix001 [56]

Answer:

1,2,3

Step-by-step explanation:

8 0
3 years ago
Entomologists estimate that an average person consumed almost a pound of bug parts each year. There are that many insect eggs, l
gregori [183]

Answer:

0.9797

Step-by-step explanation:

We have X = number of insects in the 25bgrams of butter

Then the legal limit of concentration in peanut butter = 30 fragments/ 100 grams

Then insect amount in 25 grams =

E(X) = 30/100 x 25

= 0.3 x 25

= 7.5 fragments of insects

Using the poisson function in Excel, the probability of at least 3 crunchy critters

1 - p(X<=2)

p(X<=2) = POISSON (2, 7.5, TRUE) = 0.020156715

1 - 0.020156715

= 0.9797

7 0
3 years ago
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