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3 years ago

9

Whats the figures and how do I find the area?

1 answer:

iragen [17]3 years ago

8 0

Answer:

This is trapezium.

Area of this figure =1/2h(d1-d2)

1/2×5(14-8)

=30/2

=15cm^2

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4|n|-5=7 please help me solve

DedPeter [7]

I think you meant to type

4(n)-5=7.

4n = 7 + 5

4n = 12

n = 12/4

n = 3

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The answer I would go with is A.

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Plz help ill give u brainlist

lubasha [3.4K]

Area of the front and back faces = 2 [ (8.1 x 8.1) + (1/2 x 8.1 x 2.1 ] = 148.23 in²

Area of the right and left faces = 2 [ 11.8 x 8.1 ] = 191.16 in²

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3 years ago

Simplify 3 (5x -4) = 8x -2

sweet [91]

The answer is 10/7
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Sholpan [36]

Answer:

The equation of the line in slope-intercept form is:

$y\:=\:\frac{-10}{7}x-\frac{45}{7}$

Step-by-step explanation:

Given the points

(-8, 5)

(-1, -5)

Finding the slope

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-8,\:5\right),\:\left(x_2,\:y_2\right)=\left(-1,\:-5\right)$

$m=\frac{-5-5}{-1-\left(-8\right)}$

$m=-\frac{10}{7}$

We know the slope-intercept form of the line equation is

$y = mx+b$

where m is the slope and b is the y-intercept

substituting m = -10/7 and (-8, 5) in the slope-intercept form to determine the y-intercept

$5\:=\:\frac{-10}{7}\left(-8\right)+b$

$\frac{80}{7}+b=5$

$b=-\frac{45}{7}$

now substituting m = -10/7 and b = -45/7 in the slope-intercept form

$y = mx+b$

$y\:=\:\frac{-10}{7}x+\left(-\frac{45}{7}\right)$

$y\:=\:\frac{-10}{7}x-\frac{45}{7}$

Thus, the equation of the line in slope-intercept form is:

$y\:=\:\frac{-10}{7}x-\frac{45}{7}$

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