ITS TOO SMALL TO SEE THAT PRINT, BUT CAN SOMEONE PLEASE HELP ME ANSWER THIS PROBLEM ON MY PROFILE I JUST POSTED IT AND NO ONE WILL HELP ME!!1
The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:
<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Answer:
-6
Step-by-step explanation:
is -6
Answer:
The value of k is 5/8
Step-by-step explanation:
The value of k is found by dividing the numerator of the original ratio, 5, by the sum of the numerator and denominator of the ratio
When finding a point, P, to partition a line segment AB into the ratio a/b, we find a ratio c = a / (a + b)
According to this formula we find the value of k.
k = a/(a+b)
where a = 5
b = 3
Now plug the values in the formula:
k = 5/(5+3)
k = 5/8 ....
Answer:
i honestly don't know
Step-by-step explanation:
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