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3 years ago

14

List 3 values that would make this inequality true. Y-30<43

1 answer:

Anna11 [10]3 years ago

4 0

Answer:

72.999999, 0, -10000234

Step-by-step explanation:

y-30 < 43

y < 73

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vladimir2022 [97]

Answer:

$25

Step-by-step explanation:

We know,

Monthly interest = (Principal × Interest rate) ÷ 12

Given,

Loan principal = $3,000

Interest rate = 10% = 0.10

Therefore, monthly interest = ($3,000 × 0.10) ÷ 12

Monthly interest = $300 ÷ 12

Monthly interest = $25

Therefore, the principal amount to be paid per month is = $(96.80 - 25) = $71.80.

So, Jamison will pay $25 as interest for the 36-month $3,000 loan.

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3 years ago

Which is greater than, less than, and equal to 18 tons or 36,000 lbs?

slamgirl [31]

36000 lbs = 16329.325 kg
18 ton = 18000kg

18 ton is greater

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3 years ago

. Does the model represent asexual or sexual reproduction?

LuckyWell [14K]

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Step-by-step explanation:

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2 years ago

In the figure, a ll b and m 6 = 146 degrees <br><br> What is the m 2?

levacccp [35]

Due to m<2 is a corresponding angle to m<6, the answer to the question is 146°.

5 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago