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3 years ago

What is the common denominator of 14 and 8

Mathematics

2 answers:

Akimi4 [234]3 years ago

6 0

It would be 56. The LCM of 14 and 8 is 56.

dalvyx [7]3 years ago

4 0

The common denominator between 14 and 8 is 2

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6h + 4 = 8 solve for h

Greeley [361]

Answer: h=4/6

Step-by-step explanation:

6h=8-4

6h=4 /:6

h=4/6

6 0

3 years ago

The function LaTeX: f\left(x\right)=2\cdot4^xf ( x ) = 2 ⋅ 4 xcan be used to represent an exponential growth curve. What is the

nikklg [1K]

Option B: 4 is the multiplicative rate of change of the function

Explanation:

The exponential growth function is $f(x)=2(4)^x$

We need to determine the multiplicative rate of change of the function.

First, let us determine the values of function.

x y

1 8

2 32

3 128

4 512

Since, the multiplicative rate of change of an exponential function is the number by which the next term is increasing or decreasing.

Thus, the multiplicative rate of change of the function is given by

Multiplicative rate of change of the function = $\frac{32}{8} =4$

Multiplicative rate of change of the function = $\frac{128}{32} =4$

Multiplicative rate of change of the function = $\frac{512}{128} =4$

Thus, the multiplicative rate of change of the function is 4

Therefore, Option B is the correct answer.

8 0

2 years ago

Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

7 0

3 years ago

A rectangular pyramid is sliced so the cross section is perpendicular to its base but does not pass through its vertex.

julsineya [31]

Answer:

if it's a rectangular pyramid a rectangle

Step-by-step explanation:

the cross sectional area is the shape at the bottom

6 0

3 years ago

Read 2 more answers

I need help plz help

VashaNatasha [74]

twice as many cats (as) dogs.

c = 2d [not true]

Three less than twice as many cats (as) dogs.

c = 2d - 3

210 combined,

c + d = 210

Subtracting,

-d = 2d - 3 - 210

-3d = -213

d = 71

Answer: 71

7 0

3 years ago