Answer:
Option B
Step-by-step explanation:
Formula to be used to calculate the length of an arc,
Length of arc = 
Here, θ = Angle subtended at the center by the arc
r = radius of the circle
By substituting values in the formula,
s = 
Therefore, Option B will be the answer.
9514 1404 393
Answer:
- ABHGEFDCA
- does not exist
- ECBADFE
Step-by-step explanation:
A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.
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For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.
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For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.
Answer:
Sale tax: $36.00
Total price: 9%
Step-by-step explanation:
Answer:
248
Step-by-step explanation:
(62)4
= 62 x 4
= 248
Answer:
75.9 km/hr
Step-by-step explanation:
Distance between the highway and farmhouse is given as = 2km = a
The distance after the intersection and the highway = b
Let the distance between the farmhouse and the car = c
Using the Pythagoras Theorem rule
c² = a² + b²
c² = 2² + b²
Step 1
Since distance is involved, time is required. Hence, we differentiate the equation above in respect to time
c² = 2² + b²
dc/dt (2c) = 4 + 2b
dc/dt =[ b/(√b² + 4)] × db/dt
We are told in the question that:
the car travels past the farmhouse on on the highway at a speed of 80 km/h.
We are asked to calculate the speed at which the distance between the car and the farmhouse kept increasing when the car is 6 km past the intersection of the highway and the road.
This calculated using the obtained differentiation above:
dc/dt = [ b/(√b² + 4)] × db/dt
Where b = 6km
db/dt = 80km/hr
[6/(√6² + 4)] × 80km/hr
6/√36 + 4 × 80km/hr
6 × 80/√40
480/√40
= 75.894663844km/hr
Approximately = 75.9km/hr
