How many days in 4 consecutive years

2 answers:

4 0

There are 365 days in a year.
So in 4 years, there are 365 × 4 = 1460 days.
However, every 4 years, there is also a "leap day." (an additional day in February of years divisible by 4 to balance the calendar)
After adding this day, we would have 1461 days in 4 consecutive years.
<em>
</em><em>*Note: There are exceptions to when leap years happen, so on some 4 year periods there is no leap year. In that case, there could be just 1460.</em>

FrozenT [24]3 years ago

4 0

THE ANSWER IS

365 x 4 + 1
= 1461

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kipiarov [429]

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From 4 to 5: There is a 180° rotation in the clockwise direction.

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Full Question:

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7 0

1 year ago

Use four rectangles to estimate the area between the graph of the function f(x) = V3x + 5 and the x-axis on the interval[0, 4] u

yuradex [85]

Answer:

12.123

Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

f(0) +f(1) +f(2) +f(3)

As the attachment shows, that sum is ...

area ≈ 12.123 . . . square units

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.