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Ipatiy [6.2K]
4 years ago
12

PLSS HELP I'm really stuck!

Chemistry
1 answer:
ss7ja [257]4 years ago
6 0

Answer:

The steps are explained below, the essential step is to find mass here, 120 g of NaOH.

Explanation:

In order to answer this question, we need to define molarity conceptually firstly to see what variables we need. According to the formula, molarity is equal to the ratio between moles and volume, while moles itself is a ratio between mass and molar mass. This means we have a formula for molarity involving mass, molar mass and volume:

c = \frac{n}{V} = \frac{m}{MV}

In order to prepare a 500.0 mL of stock solution of 6.0 M of NaOH, we then need to find the mass of NaOH dissolved in this solution using the equation above:

m = cMV = 6.0 M\cdot 39.997 g/mol\cdot 0.5000 L = 120 g

Now, since we have the mass of NaOH, we can describe the steps needed to prepare this solution:

  • measure 120 grams of solid NaOH;
  • add this mass of NaOH into a 500.0-mL Erlenmeyer flask;
  • fill approximately half of the flask with distilled water and stir gently to make sure that NaOH dissolves, if it doesn't, add more water and repeat the process;
  • when NaOH fully dissolves, fill the flask to the mark.

Our solution is prepared.

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How will the concentration of H+ and OH− ions change when a substance with a pH 11.4 is added to water?
PolarNik [594]

Answer is: H+ will increase and OH− will decrease.

pH = 11.4.

pH = -log[H+].

[H+] = 10∧(-pH).

[H+] = 10∧(-11.4).

[H+] = 4·10⁻¹² mol/L.

[H+] · [OH-] = 1·10⁻¹⁴ mol²/dm⁶.

[OH-] = 0.0025 mol/L.

pH value (potential of hydrogen - [H+]) is a logarithmic scale that specify the acidity or basicity of an aqueous solution.

When pH is greater than seven, aqueous solution is basic, below seven is acidic and when pH is equal seven, solution is neutral.



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4 years ago
You hold a handful of rocks and a handful of feathers. The rocks feel heavier than
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6 0
4 years ago
When silver crystallizes, it forms face-centered cubic cells. The unit cell edge length is 408.7 pm. Calculate the density of si
tester [92]

The density of silver can be calculated by using the following formula:

d=\frac{m}{V}

Here, m is mass and V is volume.

To calculate density, mass of silver needs to be calculated first.

In FCC, the number of Ag atoms in a unit cell will be 4, atomic mass of Ag is 107.87 g/mol and number of atoms in 1 mol are 6.023\times 10^{23} atoms, thus, mass can be calculated as follows:

m=4 atoms\times \frac{1 mol}{6.023\times 10^{23}atoms}\times \frac{107.87 g}{mol}=7.163\times 10^{-22} g.

Now, volume can be calculated as follows:

V=a^{3}

First convert pm to cm:

1 pm=10^{-10} cm

Thus,

408.7 pm=4.087\times 10^{-8} cm

Putting the value to calculate volume,

V=(4.087\times 10^{-8} cm)^{3}=6.83\times 10^{-23} cm^{3}

Now, calculate density as follows:

d=\frac{7.163\times 10^{-22}g}{6.627\times 10^{-23}cm^{3}}=10.5 g/cm^{3}

Therefore, density of silver is 10.5 g/cm^{3}.

3 0
4 years ago
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