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Ipatiy [6.2K]
4 years ago
12

PLSS HELP I'm really stuck!

Chemistry
1 answer:
ss7ja [257]4 years ago
6 0

Answer:

The steps are explained below, the essential step is to find mass here, 120 g of NaOH.

Explanation:

In order to answer this question, we need to define molarity conceptually firstly to see what variables we need. According to the formula, molarity is equal to the ratio between moles and volume, while moles itself is a ratio between mass and molar mass. This means we have a formula for molarity involving mass, molar mass and volume:

c = \frac{n}{V} = \frac{m}{MV}

In order to prepare a 500.0 mL of stock solution of 6.0 M of NaOH, we then need to find the mass of NaOH dissolved in this solution using the equation above:

m = cMV = 6.0 M\cdot 39.997 g/mol\cdot 0.5000 L = 120 g

Now, since we have the mass of NaOH, we can describe the steps needed to prepare this solution:

  • measure 120 grams of solid NaOH;
  • add this mass of NaOH into a 500.0-mL Erlenmeyer flask;
  • fill approximately half of the flask with distilled water and stir gently to make sure that NaOH dissolves, if it doesn't, add more water and repeat the process;
  • when NaOH fully dissolves, fill the flask to the mark.

Our solution is prepared.

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6 0
4 years ago
Sonni added 23.79 mL of KOH to 20.00 mL of 0.393 M HF until the equivalence point was reached. What is the concentration of conj
madreJ [45]

Answer:

0.1795 M

Explanation:

From the given information:

The equation is:

\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}

From the above equation, the reaction will go to completion due to the strong base:

At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)

\text{Number of moles = Volume}  \times Molarity

Thus. since moles of HF = moles of KOH

Then; 0.020 × 0.393 M = 0.02379 × (x) M

(x) M = \dfrac{0.02 \times 0.393 \ M}{0.02379}

(x) = 0.3304 M

Thus, the molarity of KOH = 0.3304 M

Using the balanced neutralization reaction;

moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol

∴

Volume = 0.020 L + 0.02379 L

Volume = 0.04379 L

Volume of the solution =  0.04379 L

Therefore; Molarity = \dfrac{moles}{volume}

Molarity = \dfrac{0.00786  \ mol}{0.04379  \ L}

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7 0
3 years ago
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