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motikmotik
3 years ago
13

How will the concentration of H+ and OH− ions change when a substance with a pH 11.4 is added to water?

Chemistry
2 answers:
PolarNik [594]3 years ago
4 0

Answer is: H+ will increase and OH− will decrease.

pH = 11.4.

pH = -log[H+].

[H+] = 10∧(-pH).

[H+] = 10∧(-11.4).

[H+] = 4·10⁻¹² mol/L.

[H+] · [OH-] = 1·10⁻¹⁴ mol²/dm⁶.

[OH-] = 0.0025 mol/L.

pH value (potential of hydrogen - [H+]) is a logarithmic scale that specify the acidity or basicity of an aqueous solution.

When pH is greater than seven, aqueous solution is basic, below seven is acidic and when pH is equal seven, solution is neutral.



Gekata [30.6K]3 years ago
4 0

Answer : The correct option is, H^+ will decrease and OH^- will increase

Explanation :

As we know that the water is made up of the H^+ and OH^- ions. When a substance with a pH 11.4 that means the solution is basic in nature is added to water, the concentration of OH^- ions increase and the concentration of H^+ ions decreases.

In the basic solution, the concentration of OH^- ions are more than the concentration of H^+ ions. So, when a base is added to the water the more OH^- ions dissociates in the water as compared to the H^+ ions.

Hence, the correct option is, H^+ will decrease and OH^- will increase

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Answer:

31^oC

Explanation:

Range = Highest value - Lowest value

A 'soft solder' melts between 183 °C and 212 °C.

Melting range of a 'soft solder' = 212-183=29^oC

A 'hard solder' melts between 620 °C and 680 °C.

Melting range of a 'hard solder' = 680-620=60^oC

So,

Difference in melting ranges = Melting range of a 'hard solder'  - Melting range of a 'soft solder' = 60^oC-29^oC=31^oC

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3 years ago
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3 years ago
The energy required for the hypothetical reaction
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Answer:

402 kJ

Explanation:

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You can determine how much energy/heat is absorbed using the balanced chemical equation. You can convert the moles A using the ratio composed of the coefficient in front of A and the energy required for each reaction.

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2 years ago
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8 0
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Answer:

{\boxed{\text{b. 2.5 g/cm}^{3}}}

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\text{Density} = \dfrac{\text{10 g}}{\text{4 cm}^{3}} = \textbf{2.5 g/cm}^{3}\\\text{The density of the crystal is ${\boxed{\textbf{2.5 g/cm}^{3}}}$}

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