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3 years ago

A die is rolled. Match the events mentioned in the first column with their corresponding probability.

Mathematics

1 answer:

lakkis [162]3 years ago

4 0

Answer:

Step-by-step explanation:

a number greater than 5 - 1/6

a prime number - 1/2

a number greater than 4 - 1/3

a number less than 6 - 5/6

You might be interested in

Work out the percentage change to 2 decimal places when a price of £110 is decreased to £98.

djyliett [7]

Answer:

10.91% decrease

Step-by-step explanation:

98/110 x 100 = 89.090909

100 - 89.0909 = 10.909090 to 2dp is 10.91%

8 0

3 years ago

Height of 10th grade boys is normally distributed with a mean of 63.5 in. and a standard deviation of 2.9 in . The area greater

lisov135 [29]

Answer:

Step-by-step explanation:

Use a calculator with probability distribution functions built-in:

normalcdf(70, 10000,63.5,2.9) = 0.013 (a little over 1%)

6 0

3 years ago

A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation

dangina [55]

Answer:

$98.9-2.62\frac{0.65}{\sqrt{103}}=98.73$

$98.9+2.62\frac{0.65}{\sqrt{103}}=99.07$

So on this case the 99% confidence interval would be given by (98.73;99.07)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=98.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=103-1=102$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that $t_{\alpha/2}=2.62$