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3 years ago

Where is the hole for the following function located? f(x)= x+3/(x+4)(x+3)

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

The answer is A

Step-by-step explanation:

Katyanochek1 [597]3 years ago

3 0

The hole of a function is described as the x-y coordinate wherein the denominator and numerator equates to zero. For the function <span>f(x)= x+3/(x+4)(x+3), the common polynomial given is x-3 which can be equated to zero. Hence, 0 divided 0 means a hole in the function. If x+3 = 0, the hole of the function is at x = -3.</span>

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A person standing 154 feet from the base of a church observed the angle of elevation to the church's steeple to be 25∘. How tall

Nookie1986 [14]

Answer:

71.764 feet

Step-by-step explanation:

See attached the rough sketch for your reference

Step one;

Given data

The angle of elevation= 25°

From the triangular diagram, we can see that the height of the church is the opposite, while the distance of the person from the church is the adjacent

Step two:

Applying SOH CAH TOA

tan∅= opp/adj

tan 25= opp/154

0.466= opp/154

cross multiply

0.466*154= opp

opp= height of church = 71.764 feet

4 0

3 years ago

What is the solution to the following system?

leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

$\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]$

Now I will shift rows to make my pivot point (top left) a 1 and so:

$\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]$

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

$\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]$

$\frac{R_2}{9}=R_2$

$\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]$

4R2+R1=R1 , -14R2+R3=R3

$\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]$

$-\frac{9}{20}R_3=R_3$

$\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]$

$-\frac{4}{9}R_3+R_2=R2$ , $-\frac{7}{9}R_3+R_1=R_1$

$\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]$

Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to". Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0

3 years ago

A jar is filled with pennies and nickels in the ratio of 5 to 3. There are 30 nickles in the jar, how many coins are there?

vladimir2022 [97]

50 pennies. 30 nickels. 80 coins in total.

7 0

3 years ago

Read 2 more answers

What’s the midpoint P(0,-2), Q(1,1

LiRa [457]

You would have to add x1 + x2 and divide by 2. do the same with y1 and y2.

(1/2,-1/2)