All categories

3 years ago

2. Determinați numărul x din:

Mathematics

1 answer:

Lana71 [14]3 years ago

5 0

Answer:

wrong language

Step-by-step explanation:

took test

You might be interested in

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Write and solve an equa

MariettaO [177]

Answer:

Steven is 15 and one half years old now

Step-by-step explanation:

Linear equations

Sometimes we need to know the value of a variable in a given equation and that variable is given as a polynomial of degree 1. Solving for that variable means isolating it and replacing the other known values

Steven was 7 years old eight and one-half years ago. If we call x as the actual age of Steven, his age eight and one-half years ago was

$x-8\frac{1}{2}$

We know he was 7 years old then, so

$x-8\frac{1}{2}=7$

We need to know his actual age, so let's solve for x, adding $8\frac{1}{2}$ to each side of the equation

$x-8\frac{1}{2}+8\frac{1}{2}=7+8\frac{1}{2}$

Simplifying

$x=15\frac{1}{2}$

Steven is 15 and one half years old now

7 0

3 years ago

A cross-country travels 20 kilometers before she realizes that she has to cover at least 75 kilometers in order to qualify for t

valina [46]

It will be 7 hour and 30 min

5 0

3 years ago

Read 2 more answers

2/3x - 21/4 = 27/4 x=

EleoNora [17]

Answer: x=-63/73

Step-by-step explanation:

Multiply both sides by 12, Move constant to the right hand side and change its sign, Move variable to the left hand side and change its sign, collect like terms, divide both sides of the equation by -73, x=-63/73 (- 63 over 73)

6 0

3 years ago

Read 2 more answers

The wettest April for Albuquerque, NM, was recorded in 1905. The amount was 1.2in more than the amount recorded for the second w

SCORPION-xisa [38]

The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2

4 0

4 years ago

This question refers to unions and intersections of relations. Since relations are subsets of Cartesian products, their unions a

Mice21 [21]

Answer:

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈ B}

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

Step-by-step explanation:

Let A = {−4, 4, 7, 9} and B = {4, 7},

Then A X B= { (-4,4),(-4,7),(4,4),(4,7),(7,4),(7,7),(9,4),(9,7)}

AXB contains all elements of A and B such that x from A and y is from B.

AXB= = {(x, y) ∈ A ✕ B| x ∈ A , y ∈ B}

R= {(-4,4),(4,4),(7,7)}

R consists all ordered pairs where |x| = |y|

R= {(x, y) ∈ A ✕ B| x R y ⇔ |x| = |y|}

S= { (-4,4),(4,4),(7,7)}

S={(x, y) ∈ x A ✕ B | S y ⇔ x − y is even}

S consists all ordered pairs where x-y is even.

R ∪ S, = { (-4,4),(4,4),(7,7)}

R US is a set containing subsets of both sets R and S

R ∪ S= {(x, y) ∈ A ✕ B | (x, y) ∈ R or (x, y) ∈ S}

R ∩ S= {(-4,4),(4,4),(7,7)}

R ∩ Sis a set containing subsets only which are common between sets R and S

R ∩ S = {(x, y) ∈ A ✕ B | (x, y) ∈ R and (x, y) ∈ S}

8 0

3 years ago