Answer:
C).
Step-by-step explanation:
-3x+2 and[(-)(x^2+5x)
3x+2 and (-x^2+5x)
3x+2-x^2+5x
-x^2-8x+2
Hope this Helps :)
Answer:
Step-by-step explanation:
- (x+y-z)²= 4xy
- (x+y-z)²- 4xy = 0
- (x+y-z)²-(2√x√y)² = 0
- (x+y-z-2√x√y)(x+y-z+2√x√y) =0
- [(√x-√y)²-z]*[(√x+√y)²-z]=0
- (√x-√y)²-z = 0 or (√x+√y)²-z = 0
We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²
so (x+y-z)²= 4xy
Use the identity P(A ∪ B) = P(A)+P(B)-P(A ∩ B)
P(A)=0.50
P(B)=0.60
P(A ∪ B) = 0.30
=>
P(A ∪ B) = P(A)+P(B)-P(A ∩ B)
=(0.50+0.60)-0.30
=0.80
Answer:
Possible derivation:
d/dx(a x + a y(x) + x a + y(x) a)
Rewrite the expression: a x + a y(x) + x a + y(x) a = 2 a x + 2 a y(x):
= d/dx(2 a x + 2 a y(x))
Differentiate the sum term by term and factor out constants:
= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))
The derivative of x is 1:
= 2 a (d/dx(y(x))) + 1 2 a
Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):
= 2 a + d/dx(x) y'(x) 2 a
The derivative of x is 1:
= 2 a + 1 2 a y'(x)
Simplify the expression:
= 2 a + 2 a y'(x)
Simplify the expression:
Answer: = 2 a
Step-by-step explanation:
Part A:
Look at the image attached to my answer for the graph of the inequalities.
There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.
The green line is 2x+y≤8, the blue line is x+y≥4
Part B:
To test if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it doesn't satisfy one of them, then it isn't included in the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less then or equal to 8
Thus, (8, 10) cannot be a solution since the inequality is not true.
Part C:
I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.
The point (2, 3) means that Sarah can buy 2 cupcakes and 3 pieces of fudge to get at least 4 pastries for her siblings while staying within her 8 dollar budget.
Let me know if you need any clarifications. Happy Studying~