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Anna71 [15]
3 years ago
15

Can someone help me find the percentage please

Mathematics
2 answers:
Lelechka [254]3 years ago
3 0
The # of meals decreased by a total of 120 - 52 = 68 meals. Now in order to find the percent decrease, you must find what total percent 68 is out of 120. 

68/120 = x/100, this ratio will give you the percent that 68 is out of 120 if you solve for x. 

Using inverse operations you get:

6800 = 120x

x = 56.7% when rounded. Meaning that the total percent decrease was about 56.7
liraira [26]3 years ago
3 0
I think it's like 56.1
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c) 10

Step-by-step explanation:

You do 5 C 3 ( because you are choosing 3 from the remaining 5).

5C3 = 5!/(3!2!) = 10

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Can someone help me please?
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Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
Sliva [168]

Answer:

  • g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
  • A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

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(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

4 0
3 years ago
3x − x − 1 = 15<br> What is x
azamat

Answer: x=8

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x−x−1=15

3x+−x+−1=15

(3x+−x)+(−1)=15(Combine Like Terms)

2x+−1=15

2x−1=15

Step 2: Add 1 to both sides.

2x−1+1=15+1

2x=16

Step 3: Divide both sides by 2.

2x /2 = 16 /2

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4 0
3 years ago
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Is u = - 1/2 a solution of 8u - 1=6u
Svetradugi [14.3K]

Answer:

No

Step-by-step explanation:

Step 1: Write equation

8u - 1 = 6u

Step 2: Solve for <em>u</em>

  1. Subtract 6u on both sides: 2u - 1 = 0
  2. Add 1 to both sides: 2u = 1
  3. Divide both sides by 2: u = 1/2

∴ u = -1/2 is NOT a solution.

7 0
3 years ago
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