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Anna71 [15]
3 years ago
15

Can someone help me find the percentage please

Mathematics
2 answers:
Lelechka [254]3 years ago
3 0
The # of meals decreased by a total of 120 - 52 = 68 meals. Now in order to find the percent decrease, you must find what total percent 68 is out of 120. 

68/120 = x/100, this ratio will give you the percent that 68 is out of 120 if you solve for x. 

Using inverse operations you get:

6800 = 120x

x = 56.7% when rounded. Meaning that the total percent decrease was about 56.7
liraira [26]3 years ago
3 0
I think it's like 56.1
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Answer:

C).

Step-by-step explanation:

-3x+2 and[(-)(x^2+5x)

3x+2 and (-x^2+5x)

3x+2-x^2+5x

-x^2-8x+2

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7 0
3 years ago
5.b) If z^(1/2)=x^(1/2)+y^(1/2) , show that (x+y-z)^2=4xy
Rudik [331]

Answer:

Step-by-step explanation:

  • (x+y-z)²= 4xy
  • (x+y-z)²- 4xy = 0
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We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²

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3 0
3 years ago
If p(a) = 0.50, p(b) = 0.60, and p(a intersection
bogdanovich [222]
Use the identity P(A ∪ B) = P(A)+P(B)-P(A ∩ B)

P(A)=0.50
P(B)=0.60
P(A ∪ B) = 0.30
=>
P(A ∪ B) = P(A)+P(B)-P(A ∩ B)
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5 0
3 years ago
Urgent answer please <br> Ax+ay+xa+ya
marin [14]

Answer:

Possible derivation:

d/dx(a x + a y(x) + x a + y(x) a)

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= d/dx(2 a x + 2 a y(x))

Differentiate the sum term by term and factor out constants:

= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))

The derivative of x is 1:

= 2 a (d/dx(y(x))) + 1 2 a

Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):

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The derivative of x is 1:

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Step-by-step explanation:

8 0
3 years ago
PLEASE HURRYY I AM BEGGING FOR HELP IVE BEEN STUCK FOR AN HOUR
saul85 [17]

Part A:

Look at the image attached to my answer for the graph of the inequalities.

There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.

The green line is 2x+y≤8, the blue line is x+y≥4

Part B:

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26 ≤ 8... 26 is NOT less then or equal to 8

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I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.

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3 years ago
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