Recall that the bullhorn acacia forms a symbiosis with p. Ferruginea ants. A researcher takes an acacia seed and plants it in an
1 answer:
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Answer:
a)
Based on the data for the group of cells, among the four proteins, protein p16 does not appear to play a role in blocking cell cycle entry by fibroblasts. The evidence for this is in group 7, where, in the absence of the other proteins the p16 presence has helped the replication of DNA almost as good as the growth in the 10% serum.
In the other groups (3 to 6) the presence of any other protein has always inhibited the DNA replication compared to the fibroblast in 10% serum.
b)
Groups 4 to 7 have higher chance of including cells undergoing mitosis as they are showing more DNA replication compared to the group 1 which has 0% serum. In this group since it has been cultured for 48 hours in the absence of serum (serum-starvation), they stop dividing and enter the G0 stage of the cell cycle.
c)
The data here would provide the crucial information on which protein is required to induce the cells to enter the cell cycle. To recover from an injury the cells should divide and repair the wound, this will happen through stimulating the cell with the required protein. It would also shed light on which protein would inhibit the cells from entry into the cell cycle.
Note: Figure is added in the attachment section
Match each field of study to the correct piece of evidence.
Answer:
19.32L
Explanation:
Given parameters:
Volume of the gas at STP = 29.3liters;
Using this information first, let us find the number of moles of the gas.
Number of moles =
With the number of moles, we can further solve this problem;
Number of moles = = 1.31 moles
More parameters;
Pressure on gas = 1.39atm
temperature = -23°C = -23 + 273 = 250K
Unknown:
Volume of gas = ?
Solution:
The ideal gas equation is the perfect fix to solve this problem.
It is mathematically expressed as;
Pv = nRT
where P is the pressure
v is the volume
R is the gas constant
n is the number of moles
T is the temperature
Input the parameters;
1.39 x V = 1.31 x 0.082 x 250
V = 19.32L