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Nikolay [14]
3 years ago
15

PLEASE HELP!

Mathematics
2 answers:
kirza4 [7]3 years ago
4 0
Equations with absolute value:

|f(x)| = k

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).

How to solve:

|f(x) | = k
- f(x) = k \: \: or \: \: f(x) = k

Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}

2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6

3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}

4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}

5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Ostrovityanka [42]3 years ago
3 0

Answer:

Equations with absolute value:

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).

How to solve:

Then:

1. |x+7|=12

x+7=12 V -x-7=12

x=5 V -x=19

x=5 V x=-19

{-19, 5}

2. |2x+4|=8

2x+4=8 V -2x-4=8

2x=4 V -2x=12

x=2 V x=-6

3. 3|3k|=27

3×3k=27 V 3×(-3k)=27

9k=27 V -9k=27

k=3 V k=-3

{-3, 3}

4. 5|b+8|=30

5×(b+8)=30 V 5×(-b-8)=30

5b+40=30 V -5b-40=30

5b=-10 V -5b=70

b=-2 V b=-14

{-14, -2}

5. |m+9|=5

m+9=5 V -m-9=5

m+9=5 V m+9=-5

Step-by-step explanation:

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Find the sum of first 20 to terms of an ap in which d is equal to 7 and 20 second term is 149​
GuDViN [60]

Answer:

1370

Step-by-step explanation:

<h3>Given</h3>
  • AP with d= 7 and a₂₂ = 149
<h3>To find</h3>
  • Sum of first 20 terms
<h3>Solution</h3>

<u>First, let's get the value of the first term:</u>

  • aₙ = a + (n-1)d
  • a₂₂ = a + 21d
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  • a = 149 - 147
  • a= 2

<u>Next, let's find the sum of the first 20 terms</u>

  • Sₙ = 1/2n(2a+ (n-1)d)
  • S₂₀ = 1/2*20(2*2 + 19*7) = 10(4 + 133) = 10*137 = 1370

<u>Answer is</u> 1370

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Step-by-step explanation:

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Step-by-step explanation:

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