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Nikolay [14]
3 years ago
15

PLEASE HELP!

Mathematics
2 answers:
kirza4 [7]3 years ago
4 0
Equations with absolute value:

|f(x)| = k

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).

How to solve:

|f(x) | = k
- f(x) = k \: \: or \: \: f(x) = k

Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}

2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6

3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}

4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}

5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Ostrovityanka [42]3 years ago
3 0

Answer:

Equations with absolute value:

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).

How to solve:

Then:

1. |x+7|=12

x+7=12 V -x-7=12

x=5 V -x=19

x=5 V x=-19

{-19, 5}

2. |2x+4|=8

2x+4=8 V -2x-4=8

2x=4 V -2x=12

x=2 V x=-6

3. 3|3k|=27

3×3k=27 V 3×(-3k)=27

9k=27 V -9k=27

k=3 V k=-3

{-3, 3}

4. 5|b+8|=30

5×(b+8)=30 V 5×(-b-8)=30

5b+40=30 V -5b-40=30

5b=-10 V -5b=70

b=-2 V b=-14

{-14, -2}

5. |m+9|=5

m+9=5 V -m-9=5

m+9=5 V m+9=-5

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The diagonals of a rhombus intersect at their midpoints and make a right angle. They also divide the angles of the rhombus in two equal angles.

So, to find the acute angle of the rhombus, we can use the tangent relation of half this angle in the small triangle made when drawing the diagonals:

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So the acute angle of the rhombus is 67.38 degrees.

Please check the image attached for better comprehension.

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