PLEASE HELP!
2 answers:
Equations with absolute value:
Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:
Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:
Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
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Given :
A sequence of numbers begins at 400.
To Find :
If the pattern increases by consecutive multiples of 5 starting with 5, then find the next 3 numbers in the sequence 400, ___, ___, ___ .
Solution :
This is the a question of arithmetic progression .
The first term is , a = 400 .
Now , it is given that the next numbers increase by the multiples of 5 starting with 5 .
So , common difference is , d = 5 .
Now , we know , number in A.P is given by :
Putting value of n = 2 , 3 , 4 .
We get :
Therefore , the next 3 numbers in the sequence is 400 , 405 , 410 , 415 .
Hence , this is the required solution .