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Jlenok [28]
3 years ago
9

Write an expression so that the product of a whole number and a decimal is.0.28

Mathematics
1 answer:
Naddik [55]3 years ago
8 0

.11+.17=.28

sorry if this is wrong i didn't know if you wanted algebraic form or not

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Step-by-step explanation:

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2.5+4 = 6.5

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PLZ do this!!! I will give brainliest to anyone who does them all right. I need this done at 3:30 (it 2:44 right now)! No fake a
leva [86]

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A: y=1/3x+5

B: y=-2x+9

C: y=-3

D:y=2x+9

E: y=-10x+80

F:y=x-2

#1 rodney's error for

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PLEASE ANSWER! Given the functions f(x) = x2 + 6x - 1, g(x) = -x2 + 2, and h(x) = 2x2 - 4x + 3, rank them from least to greatest
Ratling [72]

Answer:

<em>he rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

Step-by-step explanation:

A quadratic equation is given by:

ax^2+bx+c =0

Here, a, b and c are termed as coefficients and x being the variable.

<em>Axis of symmetry can be obtained using the formula</em>

x = \frac{-b}{2a}

Identification of a, b and c in f(x), g(x) and h(x) can be obtained as follows:

f(x) = x^2 + 6x - 1

⇒ a = 1, b = 6 and c = -1

g(x) = -x^2 + 2

⇒ a = -1, b = 0 and c = 2

h(x) = 2^2 - 4x + 3

⇒ a = 2, b = -4 and c = 3

So, axis of symmetry in f(x) = x^2 + 6x - 1 will be:

x = \frac{-b}{2a}

x = -6/2(1) = -3

and axis of symmetry in g(x) = -x^2 + 2 will be:

x = \frac{-b}{2a}

x = -(0)/2(-1) = 0

and axis of symmetry in h(x) = 2^2 - 4x + 3 will be:

x = \frac{-b}{2a}

x = -(-4)/2(2) = 1

<em>So, the rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

<em>Keywords: axis of symmetry, functions</em>

<em>Learn more about axis of symmetry from brainly.com/question/11800108</em>

<em>#learnwithBrainly</em>

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