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vaieri [72.5K]
3 years ago
12

Find the number that makes the 2 fractions equivalent 3/8=9/?

Mathematics
2 answers:
Lorico [155]3 years ago
6 0

Answer:

24

Step-by-step explanation:

The numerator of the equivalent fraction of 3/8 is 9. From this, we can see that the common factor that is being multiplied is 3. So the denominator, 8, has to be multiplied by 3 as well which gives you 24. 9/24 is an equivalent fraction of 3/8

denpristay [2]3 years ago
5 0

Answer:

Step-by-step explanation:

3/8 = 9/x

3x = 72

x = 24

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Find the sum: (n + 7) + (n - 14)
Vika [28.1K]

Answer:

<em>2n - 7</em>

Step-by-step explanation:

To get the sum you would combine like terms.

So:

n + n= 2n

7 + -14 = 7 - 14 = -7

Put it together:

2n - 7

7 0
3 years ago
Evaluate for c = -3 <br><br> 9 - c
ki77a [65]
The answer is 12 because you put -3 in the C places which gets you 9 – -3 and then you follow the signs which you would have to add them and get 12
7 0
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8/t; t=4 rkrrkrkkrkrkrkrkr
Inga [223]

Answer:

yes 12

Step-by-step explanation:

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8 0
3 years ago
What is the area of the figure?
masya89 [10]

Step-by-step explanation:

∆=3*6=18

[]=5*15=75

75+18=93 in squared

3 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
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