Let n be the larger integer and n-2 be the smaller integer.
n² - (n - 2)²
= n² - (n - 2)(n - 2)
= n² - (n² - 4n - 4)
= n² - n² + 4n + 4
= 4n + 4
= 4(n + 1)
No matter what value n is, it will always be a multiple of 4.
Answer:
1. 6/7
2. 1/2
3. 7/10
4. 39/40
5. 15/28
6. 3/10
7. 7/12
8. 1/6
9. 5/12
10. 1/8
Step-by-step explanation:
Answer:
m=-3
x1,y1=1,-5
we have,
y-y1=m(x-x1)
y-(-5)=-3(x-1)
y+5=-3x+3
3x+y+2=0 is the required eqn
Answer:
-319
Step-by-step explanation:
