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The percent of SO₂ in H₂SO₄ : 65.3%
<h3>Further explanation
</h3>
Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements
%Mass A in AxBy =
For SO₂ in H₂SO₄ :
MW SO₂ = 32 + 2.16=64 g/mol
MW H₂SO₄ =2.1+32+4.16=98 g/mol
The percent of SO₂ :
Answer:
200 mph north
Explanation:
So to answer your question, when traveling at a constant velocity of 100 mph, it will take 36 seconds to travel one mile.
0s to 15s: constant speed/zero acceleration
15s to 40s: constant gradient, therefore constant deceleration
Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol