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3 years ago

Which statement best describes the intermolecular forces between H2

Chemistry

1 answer:

Pie3 years ago

6 0

Answer:

D. Van der Waals forces are the strongest force between H2

molecules and between NH3 molecules.

Explanation:

Van der Waal’s forces are the forces which arises due to disturbance in the electron density of the molecule.

These are usually found in non polar molecules. Hence N2 is said to exhibit this force.

Out of these Van der Waals is the weakest force.

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According to Newton's third law, the two forces in a force pair act

Minchanka [31]

B. With the same force

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3 years ago

Calculate the Molarity of a 750ml Solution in which 26 grams of sodium chloride (NaCl) are dissolved

enot [183]

Answer:0.59M

Explanation:

8 0

3 years ago

What is the difference between qualitative data and quantitative data?

astraxan [27]

Quantitative data can be counted, measured, and expressed using numbers. Qualitative data is descriptive and conceptual.

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3 years ago

A constant volume of oxygen is heated from 100°C to 155°C. The

dybincka [34]

Answer:

= 3.56 atm

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure and Charles law states the volume of a given mass of gas is directly proportional to the temperature.

P1/T1 = P2/T2

P1 = 3.1 atm, T1 = 100'C = 100+273 = 373K

T2 = 155'C = 155 + 273 = 428K

3.1/ 373 = P2 / 428

Cross multiply

373 × P2 = 3.1 × 428

373×P2 = 1326.8

Divide both sides by 373

P2 = 1326.8 ÷ 373

P2 = 3.56 atm

I hope this was helpful, please mark as brainliest

3 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) $H_2SO_4$