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poizon [28]
2 years ago
7

A fish tank holds 45 gal of water. How many kilograms of water are in the fish tank?

Chemistry
1 answer:
larisa [96]2 years ago
7 0

Answer:

How to convert 45 gal to kg? You can use the following formula to convert from Gallon to Kilograms :

X(kg) = y(gal) / 0.264172053

To convert 45 Gallon to Kilograms:

X(oz) = 45(gal) / 0.264172053

Answer: 170.3435 kg

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4 . suppose you are setting up a reaction that requires an iodide salt and are planning to use sodium iodide. however, at the la
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You will need to weight out less
6 0
3 years ago
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the
weqwewe [10]

Answer:

The pressure increases by a factor of four.

Explanation:

Let's consider a gas at a given temperature and pressure (T₁, P₁). The absolute temperature of a gas is increased four times (T₂ = 4 T₁) while maintaining a constant volume. We can assess the effect on the pressure (P₂) by using Gay Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = P₁ × 4 T₁/T₁

P₂ = 4 P₁

The pressure increases by a factor of four.

4 0
2 years ago
PLEASE HELP!! I REALLY NEED HELP
Allushta [10]

Answer:

Explanation:

1. find the molar mass (amu) of each element and add them to get the whole molar mass.

2. divide the 1 element molar mass with the whole molar mass

3. multiple by 100 and that gives you the % composition.

<h2><u><em>56-57: NaCl</em></u></h2>

1. Na(22.99amu) + Cl (35.453amu)=58.443

2(Na):   \frac{22.99}{58.443} = .393

2(Cl): \frac{35.453}{58.443}= .607

3(Na): .393 * 100=39.3%

3(Cl): .607 * 100= 60.7%

<h2><u>58-60 </u>K_{2} CO_{3}<u /></h2>

1. K: (39.098)(2)=78.196

_ C: (12.011)(1)= 12.011

_O: (15.99)(3) = 47.997

78.196+12.011+47.997= 138.204

2:K: \frac{78.196}{138.204}= .566 <u>Step </u>3: (.566)(100)= 56.6%

2: C: \frac{12.011}{138.204}= .087 <u>Step 3</u>: (.087)(100)= 8.7%

2: O: \frac{47.997}{138.204}= .347 <u>Step 3</u>: (.347)(100) = 34.7%

<h2>61-62 Fe_{3} O_{4}</h2>

1. Fe (55.845)(3)= 167.535

_ O (15.999)(4) = 63.996

167.535+63.996=231.531

2: Fe: \frac{167.535}{231.531}= .724 Step 3: (.724)(100)= 72.4%

2: O : \frac{63.996}{231.531}= .276 Step 3: (.276)(100) = 27.6%

<h2>63-65 C_{3}H_{5}(OH)_{3}</h2>

1.

C(12.011*3)=36.033

H(1.008*5)=5.04 + (1.008*3)=3.024 so its 8.064

O(15.999*3)=47.997

add them: 92.094

2: C: \frac{36.033}{92.094}= .391 Step 3: (.391)(100) = 39.1%

2: H: \frac{8.064}{92.094}= .088 step 3: (.088)(100) = 8.8%

2: O: \frac{47.997}{92.094} = .521 step 3: (.521)(100) = 52.1%

3 0
2 years ago
Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4).
zavuch27 [327]

Answer : The correct option is, (B) Salicylic acid

Solution :

First we have to calculate the moles of salicylic acid and acetic anhydride.

\text{Moles of }C_7H_6O_3=\frac{\text{Mass of }C_7H_6O_3}{\text{Molar mass of }C_7H_6O_3}=\frac{70g}{138.121g/mole}=0.507moles

\text{Moles of }C_4H_6O_3=\frac{\text{Mass of }C_4H_6O_3}{\text{Molar mass of }C_4H_6O_3}=\frac{80g}{102.09g/mole}=0.783moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2C_7H_6O_3(aq)+C_4H_6O_3(aq)\rightarrow 2C_9H_8O_4(aq)+H_2O(l)

From the balanced reaction we conclude that

As, 2 moles of salicylic acid react with 1 mole of acetic anhydride

So, 0.507 moles of salicylic acid react with \frac{0.507}{2}=0.2535 mole of acetic anhydride

The excess of acetic anhydride = 0.783 - 0.2535 = 0.5295 moles

That means the in the given balanced reaction, salicylic acid is a limiting reagent because it limits the formation of products and acetic anhydride is an excess reagent.

Hence, the limiting reagent is, salicylic acid.

7 0
2 years ago
The relationships among which variable quantities are expressed by the ideal gas law equation?
Eva8 [605]

<u><em>The  variable quantities are expressed by the ideal gas law equation are; </em></u>

<u><em>pressure, volume, temperature, number of moles</em></u>

<u><em /></u>

This question is simply based on defining the ideal gas law.

  • Now, A gas is considered to ideal if its particles are so far from each other in such a manner that they don't exhibit any forces of attraction between themselves. Now, in real life this is not possible but under high temperatures and pressure, we can have something close to it and that's why ideal gas laws are very important.

  • This law states that states that the pressure, temperature, number of moles and volume of a gas are related to each other by the formula;

PV = nRT

Where;

P is pressure

V is volume

n is number of moles

T is temperature

R is ideal gas constant (This is fixed and not variable)

The  variable quantities are expressed by the ideal gas law equation are;

<em>pressure, volume, temperature, number of moles</em>

Read more at; brainly.in/question/5212853

8 0
2 years ago
Read 2 more answers
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