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Tanya [424]
3 years ago
9

In which orbital does an electron in a bromine atom experience the greatest effective nuclear charge?

Chemistry
2 answers:
asambeis [7]3 years ago
4 0

First let us determine the electronic configuration of Bromine (Br). This is written as:

Br = [Ar] 3d10 4s2 4p5

 

Then we must recall that the greatest effective nuclear charge (also referred to as shielding) greatly increases as distance of the orbital to the nucleus also increases. So therefore the electron in the farthest shell will experience the greatest nuclear charge hence the answer is:

<span>4p orbital</span>

puteri [66]3 years ago
3 0

Explanation:

As the shielding effect is the effect which occurs when electrons shield each other from being attracted by the nucleus.

The effective nuclear charge is the net effective positive charge experienced by the electrons in an atom.

The electronic configuration of bromine is as follows.

      1s^{2} 2s^{2} 2^p{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{5}

Since, 1s orbital is closure to the nucleus hence it will experience the greatest nuclear charge.

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Answer:

1. The gas law used: Dalton's law of partial pressure.

2. Pressure of nitrogen = 331 mmHg

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 592 mmHg

Pressure of Oxygen (Pₒ) = 261 mmHg

Pressure of nitrogen (Pₙ) =?

The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:

Pₜ = Pₒ + Pₙ

592 = 261 + Pₙ

Collect like terms

592 – 261 = Pₙ

331 = Pₙ

Pₙ = 331 mmHg

Therefore, the pressure of nitrogen in the sample is 331 mmHg

5 0
2 years ago
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Kipish [7]
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Edit: The unit should be atm instead of Pa, as pointed out by a nice human being.
4 0
3 years ago
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iragen [17]

Answer:

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Zina [86]
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dsp73

Answer:

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