Answer: 1.22173
Step-by-step explanation:
I think it’s a and c might be wrong though
Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
6 hours since there 2 in each hour just divid 12 in half which is 5
