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seropon [69]
3 years ago
14

What is {1.75+2x0.25+5x0.05]x24

Mathematics
1 answer:
postnew [5]3 years ago
4 0
PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction)

24(1.75+2•0.25+5•0.05)
24(1.75+0.50+0.25)
24(2.50)
=6
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Question 10 (1 point) Solve for x. 1/2+x/6=4/3
jek_recluse [69]

Answer:

The value of x for the given expression is 5 .

Step-by-step explanation:

Given expression as

\dfrac{1}{2} + \dfrac{x}{6} = \dfrac{4}{3}

Now, arrange the equation

So, \dfrac{x}{6} = \dfrac{4}{3} - \dfrac{1}{2}

<u>Taking L.C.M on right hand side </u>

Or,  \dfrac{x}{6} = \dfrac{8 -3}{6}

Or,  \dfrac{x}{6} = \dfrac{5}{6}

Or, x = \frac{5\times 6}{6}

∴  x = 5

So, The value of x = 5

Hence,The value of x for the given expression is 5 . Answer

5 0
3 years ago
Substitute r=3 and h=5 into the formula V=piR^2h then evaluate
nikitadnepr [17]

To evaluate when plugging in numerical values for variables, simply put the numerical values in the place of the corresponding variables:

V = \pi \cdot 3^2 \cdot 5

\boxed{V = 45\pi \approx 141.37}

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS THANKS
Lady bird [3.3K]

What is M when R = 200? *

Step-by-step explanation:

6 0
3 years ago
25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of
sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028

b) Probability that exactly 2 has only cats (p=0.15)

P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759

c) Probability that exactly 1 has cats and dogs (p=0.1)

P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508

8 0
3 years ago
Jesus bought 3 pairs of jeans for 71.40. how much would he need to pay for 8 pairs of jeans?
Radda [10]
He would need to $189.60 for eight pairs of jeans.
7 0
3 years ago
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