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1 year ago

Trigonometry (ASAP) (Urgent)

Mathematics

1 answer:

Olin [163]1 year ago

8 0

Answer:

h = 1.403733341286

Step-by-step explanation:

17.

the triangle of sides ‘l’ and ‘l-h’ is a right angled triangle.

Then

$\cos \theta =\frac{l-h}{l}$

Then

$l\cos \theta =l-h$

Then

$h=l-l\cos \theta$

18.

For l = 6 and θ = 40 :

$h=l-l\cos \theta$

= 6-6cos(40)

= 1.403733341286

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Vinvika [58]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The total charge in dollars for a car rental can be determined by using the function c = 0.4x + 35, where c represents the total

andrew11 [14]

Answer:

There is an initial charge of $35.00 for every mile traveled.

Step-by-step explanation:

From the question, the cost function s given as follows:

c = 0.4x + 35 .................... (1)

Where;

Total cost = c

Variable cost per mile = $0.40

Number of miles traveled = x

Total variable cost = 0.4x = 0.40 * x

Fixed cost = Initial cost = $35

From the above, the fixed cost or initial cost implies that no matter the number of miles a passenger takes, he is going to pay $35 in addition to the variable cost to pay.

From the question, for driving a distance of 100 miles we have:

Number of miles traveled = x = 100

Total variable cost = 0.40 * 100 = 40

Substituting the relevant value into equation (1), we have:

c = 40 + 35

c = 75

Since the total cost obtained above is $75.00, it therefore implies that the correct statement that justifies that the total cost for renting this car and driving a distance of 100 miles is $75.00 is "There is an initial charge of $35.00 for every mile traveled".

8 0

3 years ago

A group of 72 children completed a survey on what kind of sport they like. The choices were: Chess, Swimming, and Football. Ever

hichkok12 [17]

Answer:

$\dfrac{17}{72}$

Step-by-step explanation:

From the given information:

Total number of students, $n(U)=72$

The choices were: Chess(C), Swimming(S), and Football(F).

Everyone liked at least one sport except 7 kids, $n( C \cup F \cup S)'=7$

Chess is not an active sport; and

10 children liked Chess only, $n( C \cap F' \cap S')=10$

The probability that a randomly-chosen child from this group does not like active kinds of sport is the Probability that a student plays chess only or like no kind of sport at all.

$P( C \cup F \cup S)'+P(C \cap F' \cap S')=\dfrac{n( C \cup F \cup S)'+n(C \cap F' \cap S')}{n(U)} \\=\dfrac{10+7}{72} \\=\dfrac{17}{72}$