Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).
A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.
B) We round the number down to the nearest hundred if the last two digits in the number are 49 or below.
C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.
AAS rule can prove these triangles are congruent cuz u see two angles are marked as equal to each other but the side that’s overlapped on each other(the line the triangles are sharing) shows that the side is equal length to each other.
