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Snezhnost [94]
3 years ago
15

Dianne manufacturers Mexican and American flags. Due to the cost of color,she charges $20 for Mexican flags and $15 for American

flags. She sold twenty-eight flags and accumulated $460. How many flags of each type did she sell?
Mathematics
2 answers:
enyata [817]3 years ago
8 0
I got 11 Mexican and 16 American.

20 x 11 = 220
15 x 16 = 240

Which equals 460
DiKsa [7]3 years ago
5 0

Answer:

She sold 20 american flags and 8 mexican flags.

Step-by-step explanation:

In order to solve this we first have to do an equation, we will represent the american flag with the letter x, the mexican flag with y, so the amount of flags sold will be x+y=28, that would be our first equation, and the second will be 15x+20y=460.

We have both of out equations so now we just clear from x from the first one to get:

x=28-y

and insert that as value of x in the second one:

15x+20y=460

15(28-y)+20y=460

420-15y+20y=460

5y=40

y=8

Since y=8 we know that x= 20

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