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Gre4nikov [31]
3 years ago
12

Using elimination solve x+4y=-8 and x-4y=-8

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0
Subtract the two equations: 8y=0 
y=0
x=-8
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Divide £21 in ratio 3:4
xxMikexx [17]
3+4 = 7
so
21 / 7  3

3 x 3 = 9
3 x 4 = 12

answer
£21 in ratio 3:4 is £9:£12
3 0
4 years ago
I need help with this problem if anyone can help ASAP please help !
MakcuM [25]

Answer:

42

Step-by-step explanation:

7 0
3 years ago
What is five-eights divided by four?<br> Please answer using fractions!<br> Will give brianliest
bearhunter [10]

Answer:

5/8 ÷ 4 = 5/32

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
at an animal shelter there are 15 dogs 12 cats 3 snakes and 5 parakeets. what percent of the number of cats is the number of sna
dsp73
Percentage of cats
\frac{# animals}{#cats} = \frac{100}{?}
\frac{35}{12}=  \frac{100}{?} &#10;
**cross multiply 12 and 100 which is 1200
**divide 35 into 1200
the answer is 34.3% when rounded

percentage of snakes
\frac{# animals}{#snakes} = \frac{100}{?}
**cross multiply 3 and 100 which is 300
<span>**divide 35 into 300</span>
<span>\frac{35}{3}= \frac{100}{?}
</span>the answer is 8.57%
7 0
3 years ago
You can upgrade lighting at your factory to LED bulbs that coast 6.95 each and last an average of 5 years.
miskamm [114]

Answer:

$200

Step-by-step explanation:

Here is the full question

You can upgrade lighting at your factory to LED bulbs that cost $6.95 each and last an average of 5 years. It costs $3 in labor to change a bulb. Over a 10-year period, about how much will it cost per year to install LED bulbs in 100 lamps and change the bulbs when they burn out?

in 10 years, the bulbs would be changed twice

Total cost incurred per bulb in 10 years = (6.95 +  $3) x 2 = $19.90

Since there are 100 bulbs, total cost incurred would be - $19.90 x 100 = $1990

Cost per year = $1990 /  (6.95 +  $3) = $200

3 0
3 years ago
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