Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
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Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
Answer: x = 0
because the shape is a square
=> 2x + 4 = 4
⇔ 2x = 0
⇔ x = 0
Step-by-step explanation:
Answer:
She has 499.3$
Step-by-step explanation:
870+35.90+35.90+150-82.50-10-500
Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation
3y-7=41
Add 7 to both sides
3y=48
Divide both sides by 3
y=16
Now to find PN.
Based on what we know, we can assume that MP = PN. Let's make some equations!
MP = 17x-8 PN = 11x+4
17x-8 = 11x+4
Subtract 11x from both sides
6x-8 = 4
Add 8 to both sides
6x = 12
Divide by 2
x=2
Substitute 2 in for x in the equation for PN
11(2)+4
Multiply 11 by 2
22+4 = 26
PN = 26