Simply this expression (-0.25x- 3)

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago

Help please will mark brainliest.

swat32

Answer: the ANSWER IS 11 sqt

Step-by-step explanation:

Factor 1331 into its prime factors

1331 = 113

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :

121 = 112

Factors which will remain inside the root are :

11 = 11

To complete the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :

11 = 11

The simplified SQRT looks like this:

11 • sqrt (11)

Simplified Root :

11 • sqrt(11)

7 0

3 years ago

Read 2 more answers

For hw plss help!!!!

yarga [219]

Answer:

4th term is 274.4 cm

5th term is 192.08 cm

Step-by-step explanation:

Here, we want to get the 4th and 5th term

Let us get the common ratio;

That would be ;

392/560 = 560/800 = 0.7

The 4th term will be ar^3

= 800 * 0.7^3 = 274.4

The 5th term will be ar^4

= 800 * 0.7^4 = 192.08

6 0

2 years ago

3x + 2 = 2x + 6<br><br><br> Please hurry

telo118 [61]

Answer:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 4

Step-by-step explanation:

I hope this helps! Have a good day!

3 0

2 years ago

Read 2 more answers

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank

ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = $(3.78541)(1000) ml$ = 3785.41 ml.

13.4 gallon = $(3785.41)(13.4)$ ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = $\frac{x}{50724.494}$

So we can write,

$0.737 =\frac{x}{50724.494}$

To find x we will multiply both sides by 50724.494. we will get,

$(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)$

$(0.737)(50724.494) = x$

$37383.95 = x$

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

5 0

3 years ago

Simply this expression (-0.25x- 3) - (1.5x +1.4)