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Crank
3 years ago
12

How do I completely factor 4x^2-64?

Mathematics
2 answers:
NikAS [45]3 years ago
6 0
This is how you will completely factor your equation: 4(x^2-16)<span />
Salsk061 [2.6K]3 years ago
4 0
4x^2 - 64

= 4(x + 4) (x - 4)


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nekit [7.7K]
Suppose m∠1 = x degree

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