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3 years ago

15

If DH=4x-2 and FH=x+28, find the value of x for which DEFG must be a parallelogram.

1 answer:

Mnenie [13.5K]3 years ago

8 0

Given that DH=4x-2 and FH=x+28, the value of x which will make DEFG a parallelogram will be given as follows;
4x-2=x+28
4x-x=28+2
3x=30
thus
x=30/3
x=10
The answer is C] 10

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