Question

Use the given graph to determine the limit, if it exists.

Answer 1

Lim x→2-  f(x) = 3
Lim x→2+ f(x) = -2

Lim x→2-  f(x) = 3 is different to -2 = Lim x→2+ f(x), then the limit when x tends to 2 does not exist.

Answer: The limit does not exist.

Answer 2

Answer:

The limit of the function does not exist.

Step-by-step explanation:

If $lim_{x\rightarrow c}f(x)\rightarrow L$, then L is the limit of the function at x=c.

The limit of a function exist if left hand limit at a point is equal to the right hand limit at that point.

$lim_{x\rightarrow c^-}f(x)=lim_{x\rightarrow c^+}f(x)$

From the given graph it is clear that the left hand limit of the function is

$lim_{x\rightarrow 2^-}f(x)=3$

The right hand limit of the function is

$lim_{x\rightarrow 2^+}f(x)=-2$

Since $lim_{x\rightarrow c^-}f(x)\neq lim_{x\rightarrow c^+}f(x)$, therefore the limit of the function does not exist.