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Anna007 [38]
3 years ago
8

You want to deliver a package to japan.the fed ex delivery service charges a $15 flat fee plus $2 per additional kilogram. You c

an also use the usps priority mail service which charges you $5 per kilogram
Mathematics
1 answer:
Blababa [14]3 years ago
7 0
Depending on how heavy the package is, you should take the Fed Ex if the package is heavy, and the UPS for something that is small
You might be interested in
Help plz ASAP for 20pts
Paul [167]

Answer:

Not sure if this is correct but this is what I found.

area of sector=74.84

radius = 8

angle of sector=?

74.84=1/2×8²×angle of sector

74.84=32 × angle of sector

74.84/32= angle of sector

2.33875=angle of sector

Step-by-step explanation:

Sorry if it is incorrect.

4 0
3 years ago
The corresponding sides of ΔABC and ΔDEF have equal lengths. The area of ΔABC is 4 square units, and the longest side of ΔDEF is
lisabon 2012 [21]

Answer:

  4 square units

Step-by-step explanation:

If the triangles have corresponding sides the same length, they are congruent triangles. Any measure of ΔABC is the same for ΔDEF.

The area of ΔDEF is 4 square units.

3 0
3 years ago
Suppose you can afford only $200 a month in car payments and your best loan option is a 60-month loan at 3%. How much money coul
g100num [7]

Answer:

  $11,130.47

Step-by-step explanation:

The amortization formula can be used. It tells you the monthly payment amount A for some principal P, interest rate r, and n payments.

  A = P(r/12)/(1 -(1 +r/12)^(-n))

Filling in your values, we get ...

  200 = P(.03/12)/(1 -(1 +.03/12)^-60) = P(.0025)/(1 -1.0025^-60)

  P = 200(1 -1.0025^-60)/.0025 ≈ 200×55.6523577

  P ≈ 11,130.47

The present value of the loan is $11,130.47.

8 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
Need the answer pls!!!!!
damaskus [11]
The answer is -3

......
3 0
3 years ago
Read 2 more answers
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