Ellipse area = PI * a * b
ellipse area = 3.14 * 8 * 7
ellipse area = 175.84
<span>P(x) = –x4 + x3 + 7x2 − x − 6
The graph will look like a bell, or a downward facing parabola, since the dominant term is -x^4
The graph has a y-intercept of -6, which can be considered the fixed cost (cost of zero trees cut) and moves upward from there, eventually reaching a maximum at some positive number of trees and dropping again. As x gets very large, profit becomes a very large negative number. Since we can't have negative trees cut, we're only interested in positive x values
The company breaks even at P(x) = 0
0 = </span> –x4 + x3 + 7x2 − x − 6, x greater than zero
0 = (x+2)(x+1)(x-1)(x-3)
The company breaks even at 1 tree and 3 trees.
Answer:
A decimal number can be divided in a decimal part, a whole part and the decimal point which separates the first two.
So, all numbers that are placed leftside of the decimal point can be classified in units, tens, hundreds, thousands, and so on. Basically, each value depends on a base of 10. This means that thousands are ten times more than hundreds, hundreds are ten times more than tens, tens are ten times more than units.
If we want to a specific value of the whole part in a decimal number, we just need to look units, tens, hundreds, thousands or millions.
For example, if we have the number 1235.8456, the whole part would be 1235, and the value of the numbers that are leftside of the decimal point is 1235 units.
I think the answer is D. The other answers are unreasonable. Wyatt would not get the promotion and just because Tammy's lowest value is bigger than Wyatt's doesn't mean that Tammy gets the promotion. The only reasonable answer is D.
Answer:
Cpk = Cpu = Cpl = 0.4785
Step-by-step explanation:
Solution:-
- The capability of a process is determined using the capability index ( Cpk ). The index helps in determining the output of the process lies within the specification limits.
- The key dimension on a product measure is:
105 ± 12 units
- Process is producing this product at a 6-sigma quality standards i.e ( process is producing this product has a standard deviation (σ) of three units.)
Where, Standard Error in measured value = 12 units.
- The process capability (Cpu) is defined based on the Upper Specification Limit of the process (USL):
Cpu = (USL - u) / 3σ
- The process capability (Cpl) is defined based on the Lower Specification Limit of the process (LSL):
Cpl = ( u - LSL) / 3σ
- Assume that the process is centered with respect to specifications, then the given absolute value of u = 105 units.
Where the specification limits are defined as:
LSL = u - SE = 105 - 12
LSL = 93 units
USL = u + SE = 105 + 12
USL = 117 units
- Now evaluate the Process capability on each of the two limits specification limits:
Cpu = (USL - u) / 3σ
Cpu = (117 - 105) / 3σ
Cpu = 4 / σ
Cpl = ( u - LSL) / 3σ
Cpl = ( 105 - 99 ) / 3σ
Cpl = 4 / σ
- The minimum of Cpu and Cpl is denoted as the Cpk value:
Cpk = min ( Cpu , Cpl )
Cpk = Cpu = Cpl = 4 / 8.36
Cpk = Cpu = Cpl = 4 / 8.36 = 0.4785