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mart [117]
3 years ago
15

. In a class of students the ratio of the number of students who like to play football and the number of students who like to pl

ay volleyball is 5:3. If the number of students who like volleyball only is 15 and the number of students who like football only is 35, then a. Find the number of students who like both games​
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-ratios-prop-topic/intro-to-ratios/v/ratios-intro

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5.Square Given:a =12m,A=<br>Pa help po​
bixtya [17]

If s=side, then each side is 12m.

It got cut off but

12mx12m=144m^2 because mxm=m^2.

heart if helpful

5 0
3 years ago
Casey travels from her house directly west to the bank and then directly north from the bank to the mall. She then travels home
castortr0y [4]

Answer:

D) 40 miles

Step-by-step explanation:

First we must find the distance between the mall and the house.  The figure formed is a right triangle.  The length of the side from the mall to the house forms the hypotenuse of the triangle.  We can use the Pythagorean theorem to find the length:

a² + b² = c²

The two legs of the triangle, a and b, are 15 and 8:

15² + 8² = c²

225 + 64 = c²

289 = c²

Take the square root of each side:

√289 = √(c²)

17 = c

This makes the total distance

15+8+17= 40 miles

4 0
3 years ago
Read 2 more answers
What is 12,430,000 in expanded form?
Nady [450]
10,000,000+2,000,000+400,000+30,000
3 0
3 years ago
Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
NEED HELP WITH BOTH PLZ
Natalija [7]
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
7 0
3 years ago
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