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vfiekz [6]
3 years ago
12

PLEASE ANSWER HELP ME PLZ ALL THE ONES WITH QUESTION MARKS

Mathematics
2 answers:
Darya [45]3 years ago
8 0
36 minutes is all it would takr
spayn [35]3 years ago
7 0
Hello!

The answer to the first question is C 36min.
We find this by using speed=distance/time and converting units so

Time=distance/speed
Time=21miles/35mph(60min/1hr)=36min

I can’t see the last question answers clearly so I don’t want to guess but it would be a linear relationship being that cost is directly proportional to miles driven.
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Solve for v.<br> 19v – 18 = 16 + 17v
GarryVolchara [31]

Answer:

v= 17

Step-by-step explanation:

Start with the given equation.

19v – 18 = 16 + 17v

Move -18 to the other side, and swap it's sign.

19v = 16 + 18 + 17v

Move 17v to the other side and swap it's sign.

19v - 17v = 16 + 18

Combine like terms.

2v = 34

Divide by 2v.

v = 17

8 0
3 years ago
Read 2 more answers
I need help please ASAP and I will mark branlist
Lady_Fox [76]
7- B
8- C
I’m pretty sure please don’t hurt me if I’m wrong
8 0
4 years ago
The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.
OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

Step-by-step explanation:

From the information given, the equation of motion of the object is

s(t)= -16t^2+208t+156

For any equation of motion s(t), the instantaneous velocity at time t is given by

v(t)=\frac{ds}{dt}

(a) To find the object's velocity at t = 7, you must:

v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208

Next, we evaluate when t = 7

v(7)=-32(7)+208=-224+208\\\\v(7)=-16

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}

Next, we substitute this value into the equation of motion to find the maximum height

s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

6 0
3 years ago
−5 2/3+3 1/4+(−713)=
LenaWriter [7]
−5 2/3+3 1/4+(−713) the answer is =
−715.416667
7 0
3 years ago
Read 2 more answers
An angle measures 110.8° more than the measure of its supplementary angle. What is the measure of each angle?
stealth61 [152]

Answer:

34.6 and 145.4

Step-by-step explanation:

x+(x+110.8) = 180

2x= 180-110.8

2x= 69.2

x= 34.6

Measure of each angle:

x= 34.6

x+110.8 = 34.6 + 110.8 = 145.4

3 0
3 years ago
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