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kvasek [131]
2 years ago
11

The area of the trapezoid is 30square inches.

Mathematics
1 answer:
AysviL [449]2 years ago
7 0

Answer:

the height is 7.5

Step-by-step explanation:

30 divided by 4 = 7.5

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ok go to there account message them and then is says block user or report user

Step-by-step explanation:

6 0
3 years ago
Which of the following is a solution of 4x2 = − 9x − 4?
Arte-miy333 [17]

Step-by-step explanation:

4x2=−9x−4

Step 1: Subtract -9x-4 from both sides.

4x2−(−9x−4)=−9x−4−(−9x−4)

4x2+9x+4=0

For this equation: a=4, b=9, c=4

4x2+9x+4=0

Step 2: Use quadratic formula with a=4, b=9, c=4.

x=

−b±√b2−4ac

2a

x=

−(9)±√(9)2−4(4)(4)

2(4)

x=

−9±√17

8

x=

−9

8

+

1

8

√17 or x=

−9

8

+

−1

8

√17

8 0
3 years ago
To pass her test, Tori needs to answer at least 65% of the questions correct. If there were 60
aliina [53]
1) change 65% to a decimal = .65

2) .65 • 60 = 37.2 questions need to be right

3) since she got 42 correct, that is greater than 37.2, so she passed.

OR

1) 42/60 = 0.7

2) 0.7 to a percent = 70%

3) since she got a 70% on the test, she passed.
8 0
3 years ago
Read 2 more answers
Which statement is true?
diamong [38]

3 is correct , base is never equal to 1 cause all of solves of logarithm will be 0

7 0
3 years ago
Read 2 more answers
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

<em>Let p = </em><u><em>proportion of the students who are in favor of Mike.</em></u>

So, Null Hypothesis, H_0 : p \leq 50%      {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, H_A : p > 50%      {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students body in favor of Mike = \frac{55}{100} = 0.55

           n = sample of students taken = 100

So, <em><u>test statistics</u></em>  =   \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

                               =  1.01

The value of z test statistics is 1.01.

<em>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</em>

<em>Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0
3 years ago
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