Answer:
it would end at 12:25 pm. We can not see problem one.
Step-by-step explanation:
The intersecting chords theorem states that whenever two chords intersect, the product of their pieces is constant.
So, in this case, we have
![\overline{RW}\cdot\overline{WP}=\overline{SW}\cdot\overline{WQ}](https://tex.z-dn.net/?f=%5Coverline%7BRW%7D%5Ccdot%5Coverline%7BWP%7D%3D%5Coverline%7BSW%7D%5Ccdot%5Coverline%7BWQ%7D)
Plugging your values, we have
![8\cdot 9 = 6x \cdot 12x \iff 72=72x^2 \iff x^2=1](https://tex.z-dn.net/?f=8%5Ccdot%209%20%3D%206x%20%5Ccdot%2012x%20%5Ciff%2072%3D72x%5E2%20%5Ciff%20x%5E2%3D1)
This equation has solutions
, but we can't choose
, because it would lead to
![\overline{SW}=-6,\quad\overline{WQ}=-12](https://tex.z-dn.net/?f=%5Coverline%7BSW%7D%3D-6%2C%5Cquad%5Coverline%7BWQ%7D%3D-12)
So, the only feasible solutions is ![x=1](https://tex.z-dn.net/?f=x%3D1)
Answer:
Step-by-step explanation:
The possible outcomes include 1, 2, 3, etc., up through 25. This in itself is insufficient to specify who will go first. There must be some further criteria.
Suppose each player chooses and announces a number from this set by writing it down on a scrap of paper which is placed face-down on the table. The person who chooses the smaller number goes first. Or, the person who chooses the larger number goes first.
Answer:
Its C i think. Sorry if Im wrong
Step-by-step explanation:
Answer:
AB = 10, BC = 10
Step-by-step explanation:
AB = length of segment AB = sqrt( (-3-5)^2 + (-4-2)^2 ) = sqrt( 64 + 36) = sqrt(100) = 10
BC = sqrt( (5-11)^2 + (2-(-6))^2 ) = sqrt( 36 + 64 ) = sqrt( 100 ) = 10