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3 years ago

15

There are 32 students in the seventh-grade class and 25 students in the eighth-grade class at OLV. What percent is the seventh-g

rade class of the eighth-grade class at OLV? *

1 answer:

Artyom0805 [142]3 years ago

5 0

Answer:78%

Step-by-step explanation:

divide 25 by 32

then round 0.78125 to 0.78

move the decimal 2 places giving you 78%

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the room charge for a hotel is 230$ each day. the estevez family spends 4 days on vacation at the hotel . at the end of their st

DochEvi [55]

10% of 230 is 23 so
230
+23 =
253
hope i helped:)

3 0

3 years ago

Read 2 more answers

For all of the questions <br>with method <br>thankyou

Dmitry_Shevchenko [17]

Answer:

(i) 7/10

(ii) 3/10

(iii) 1/5

(iv) Rs 40,000

Step-by-step explanation:

The fraction of the salary spent on food = 1/2

The fraction of the salary spent on rented house fee = 1/5

(i) The fraction spent for both food and rental fee = (1/2) + (1/5) = (5 + 2)/10 = 7/10

(ii) The remainder (rest) of the salary = 1 - 7/10 = 3/10

The fraction of the remainder spent for children's education = 1/3

The fraction of the total salary spent for the children's education = (1/3) × (3/10) = 1/10

(iii) The remaining portion deposited in the bank = 1 - (1/10 + 7/10)) = 2/10 = 1/5

(iv) The amount equal to portion of 1/5 of his salary deposited in the bank is Rs 8000

Let <em>x</em> represent his whole salary, we have;

(1/5) × x = Rs 8,000

x = 5 × Rs 8,000 = Rs 40,000

His whole salary is Rs 40,000.

3 0

3 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago

Let the function f be defined by f(x)=12-5x b)evaluate f(-1)

Alexxx [7]

F(-1) = 12 - 5(-1)
f(-1) = 12 + 5
Solution: f(-1) = 17

6 0

3 years ago

Read 2 more answers

How is this expression written with exponents? 3 . 3 . x . x . x . x

marin [14]

Solve:-

Write it down again:-

3 · 3 · x · x · x · x

We will write it like this:-

3 · 3 · x³

7 0

3 years ago