First get everything to one side by adding 9 to 2x + 3 and you end up with 2x + 3 + 9 > 0 and you add 9 and 3 and it will be 2x + 12 > 0 and do the same for the second one but if your trying to solve for x, subtract the 3 on both sides and you will get 2x > -12 then you divide 2 by both sides and you get x which is
x > -6
➣ Assignment: 
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➣ Answer: 
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Explanation: ↓↓↓↓↓
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➤ [ Step One ] Multiply Both Sides By -1 (Reverse Inequality)

➤ [ Step Two ] Simplify

➤ [ Step Three ] Divide Both Sides By 14

➤ [ Step Four ] Simplify

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Answer:
They are used in place fir an unknow value
Step-by-step explanation:
Answer:
Below in bold
Step-by-step explanation:
∫ dx / (x^2√(9-x^2))
Substitute x = 3sinu and dx = 3cosu du
then the √(9-x^2) = √( 9 - 9sin^2u) = 3 cos u and u = arcsin(x/3)
= 3 ∫(csc^2 u du )/ 27
= 1/9 ∫(csc^2 u du
= -1/9 cot u
= -√9-x^2) / 9x.