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Elenna [48]
3 years ago
10

Find the equation of the solution to dydx=x6y through the point (x,y)=(1,3).

Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0
Separate the x's and y's.

dy/y = x^7 dx

Integrate both sides.

ln(abs(y)) = (x^8)/8 + C

To cancel the natural root, make both sides the power to e.

e^ln(abs(y)) = e^((x^8)/8 + C)

abs(y) = e^C * e^((x^8)/8)

y = + or - [e^C * e^((x^8)/8)

Now just bundle the + or - e^C into a single constant. We will call it A.

y = Ae^((x^8)/8)

Now plug in the point (1,3).

3 = Ae^((1^8)/8)

3 = Ae^(1/8)

A = 3/(e^(1/8))

So the equation is:

y = (3/(e^(1/8))*(e^((x^8)/8)






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The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

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C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

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The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

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