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Fudgin [204]
3 years ago
5

Which rule explains why these scalene triangles are similar?

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

D. None of the above; the triangles cannot be proven similar

Step-by-step explanation:

There are no signs that shows the triangles are similar or congruent for given information. So the answer is last option :

D. None of the above; the triangles cannot be proven similar

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a parking lot has total of 60 cars and trucks. the ratio of cars to trucks is 7:3 how many cars are in the parking lot. How many
Lerok [7]
7+3=10
60/10=6
6x7=42
6x3=18
there is 18 trucks in the parking lot
7 0
3 years ago
Which is the graph of g(x) = 2x – 1 + 3? On a coordinate plane, an exponential function has a horizontal asymptote at y = 3 and
IceJOKER [234]

Answer:

Graph D

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Write sin(19°) in terms of cosine.
Leto [7]

Answer:

cos(71)

Step-by-step explanation:

Since 19° is less than 90, we can express this in terms of confunction.

sin(θ) = cos(90-θ)

sin(19) = cos(90-19)

sin(19) = cos(71)

3 0
3 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
Which equation is equivalent to the formula below?
ehidna [41]

Answer:

B-is correct

Step-by-step explanation:

y=a(x-h)^2+k

-k               -k

y-k=a(x-h)^2

:(x-h)^2    :(x-h)^2

(y-k)/(x-h)^2 =a

3 0
3 years ago
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