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attashe74 [19]
3 years ago
5

Q, S, T, and U are coplanar: true or false? Why?

Mathematics
1 answer:
inysia [295]3 years ago
7 0
I think it would be true because they are crossing
You might be interested in
What is the exact area of a circle with a diameter of 20 cm?
Kisachek [45]
Hi there! The answer is 100πcm^2

The radius of a circle can be found by dividing the diameter by 2. In other words : the radius is half of the diameter.
Therefore, the radius of a circle with a diameter of 20 cm is 10 cm.

The exact area of a circle can be found using the following formula:
a = \pi \times \: {r}^{2} \\ with \\ a = area \\ r = radius

In order to find our answer, we need to plug in the data from the question.
a = \pi \: \times {10}^{2} = 100\pi

Hence, the answer is 100πcm^2.
5 0
3 years ago
SOME ONE PLEASE HELP !!!!
Andrei [34K]

x = 20 - -5 = 20 + 5 = 25

y = 16 - 1 = 15

<h2>x = 25</h2><h2>y = 15</h2>

7 0
3 years ago
Can someone help me answer this
irinina [24]

Answer:

if b = e??

what are the drop down options?

4 0
3 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
If z=3−5i, find |z|.
geniusboy [140]

Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane.  In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number.  Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point.  Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5.  To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem.  Therefore:

|z|=\sqrt{(3)^2+(-5)^2} and

|z|=\sqrt{9+25} and

|z|=\sqrt{34}

5 0
3 years ago
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