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2 years ago

if you paid $12000 for stock that was $ 8 per share and then sold all shares for 15000 how much profit did you make ?

Mathematics

2 answers:

quester [9]2 years ago

4 0

You would have a profit of $3,000

nikklg [1K]2 years ago

3 0

You would make 2$ per each share.

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Tell whether the data in the table can be modeled by a linear equation. Explain.

anastassius [24]

Answer:

y = -3x + 7

Step-by-step explanation:

Choosing two points from the given table:

Let (x1, y1) = (-3, 16)

(x2, y2) = (-1, 10)

Plug these given values into the slope formula:

m = (y2 - y1)/(x2 - x1)

= (10 - 16) / (-1 - (-3))

= -6 / (-1 + 3)

= -6/2

= -3

Therefore, the slope is -3.

Next, choose one of the points and plug into the point-slope form:

Let's use (-1, 10) as (x1, y1):

y - y1 = m(x - x1)

y - 10 = -3(x - (-1))

y - 10 = -3(x + 1)

y - 10 = -3x - 3

Add 10 on both sides to isolate y:

y - 10 + 10 = -3x - 3 + 10

y = -3x + 7

8 0

2 years ago

For two functions, m(x) and p(x), a statement is made that m(x) = p(x) at x = 7. What is definitely true about x = 7? (2 points)

Virty [35]

A)Both m(x) and p(x) cross the x-axis at 7.
B)Both m(x) and p(x) cross the y-axis at 7.
C)Both m(x) and p(x) have the same output value at x = 7.
D)Both m(x) and p(x) have a maximum or minimum value at x = 7.

m(x) = p(x) at x = 7

True statement about x = 7.
C)Both m(x) and p(x) have the same output value at x = 7.

7 0

3 years ago

Read 2 more answers

The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y

Lelechka [254]

Given the next quadratic function:

$y=2x^2+3x-2$

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

$x_V=\frac{-b}{2a}$

where a and b are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

$\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}$

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

$\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}$

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get: