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Dennis_Churaev [7]
3 years ago
10

An airplane cuts through the morning sky. For every 1,000 feet that it climbs, the outside temperature drops 20 degrees Fahrenhe

it. What is the rate of temperature change in degrees Fahrenheit per foot? Complete the steps below to answer the question.
part A: Write the change in elevation and the change in temperature as rational numbers.

part B: Write a numerical expression to represent the rate of temperature change in degrees Fahrenheit per foot.

part C: What is the rate of temperature change in degrees Fahrenheit per foot?

part D: Now, consider the reverse situation: as the airplane descends, or drops, 1,000 feet in the air, the temperature rises 20 degrees Fahrenheit. Write a numerical expression representing the rate of temperature change in degrees Fahrenheit per foot.

part E: What is the rate of temperature change in degrees Fahrenheit per foot?

part F: How is the rate you found in part E related to the rate you found in part C? What does this mean?

I've been stuck on this for so long and I think today is my last day to finish it and I haven't been able to concentrate or focus all day
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
8 0

The air plane is rising so the change in elevation is +1000 feet. The temp dropped and is -20 degrees fahrenheit.

1 degree per 50 ft

For every 1,000 feet that it climbs, the outside temperature drops 20 ... What is the rate of temperature change in degrees Fahrenheit per foot.

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Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

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2 years ago
What type of Symmetry
nikklg [1K]

Answer:

Line Symmetry, Horizontal and Vertical Lines, 90 and 180 degrees

Step-by-step explanation:

It is line symmetry because you can fold the H, and it would overlap perfectly.

Horizontal and vertical lines because if you were to place a line in the middle both horizontally and vertically it would overlap.

90 and 180 degrees because the H would still have have symmetry if you flipped it on its side or upside down.

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1 year ago
Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).
kirill115 [55]

Answer:

The Correct option is Last one y=-4x-4

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line y=-4x-3 is y=-4x-4

Step-by-step explanation:

Given:

y=-4x-3

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

y=-4x-3 ..........Given

Comparing with Slope-Intercept form,  

y=mx+c

Where m =slope  

We get

Slope = m = -4

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

(y-y_{1})=m(x-x_{1})

Substituting the points and so we will get the required equation of the line,

(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line y=-4x-3 is y=-4x-4

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