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3 years ago

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. x-8=8-x

Mathematics

1 answer:

Reil [10]3 years ago

3 0

Hello!

Answer:

One solution (8)

Step-by-step explanation:

Hope this helps!

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5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$

5 0

4 years ago

Factorise fully<br>14x – 8

andriy [413]

Answer:

2(7x-4)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Number 8 and 9 pls, if u answer u get brainlist rank!

mylen [45]

Answer:

Denote the equation : y = ax + b

Use the first 2 values of x and y in table:

3a + b = 21

5a + b = 35

Subtract the 2 equations:

=> 2a = 14 => a = 7 => b = 21 - 3 x 7 = 0

=> The solution is y = 7x

Denote the equation : y = ax + b

Use the first 2 values of x and y in table:

5a + b = 17

10a + b = 22

Subtract the 2 equations:

=> 5a = 5 => a = 1 => b = 17 - 5 x 1 = 17 - 5 = 12

=> The solution is y = x + 12

Hope this helps!

8 0

3 years ago

What would be the solution to this problem

lozanna [386]

Angle A: 60 degrees
Angle B: 30 degrees
Angle C: 90 degrees

7 0

3 years ago

Consider the function f(x)= 2/5x-4

Gre4nikov [31]

Answer: a) $\frac{5}{2}x+10=f^{-1}(x)=g(x)$

Step-by-step explanation:

Since we have given that

$f(x)=\frac{2}{5}x-4$

a.) Find the inverse of f(x) and name it g(x).

Let f(x) = y

So, it becomes

$y=\frac{2}{5}x-4$

Switching x to y , we get

$x=\frac{2}{5}y-4$

$5x=2y-20\\\\5x+20=2y\\\\\frac{5x+20}{2}=y\\\\\frac{5}{2}x+10=y\\\\\frac{5}{2}x+10=f^{-1}(x)=g(x)$

b) . Use composition to show that f(x) and g(x) are inverses of each other.

$\mathrm{For}\:f=\frac{2}{5}x-4\:\\\\\mathrm{substitute}\:x\:\mathrm{with}\:g\left(x\right)=\frac{5}{2}x+10\\\\=\frac{2}{5}\left(\frac{5}{2}x+10\right)-4\\\\=x$

Similarly,

$\mathrm{g\left(x\right)=\frac{5}{2}x+10,\:f\left(x\right)=\frac{2}{5}x-4,\:g\left(x\right)\circ \:f\left(x\right)}\\\\\mathrm{For}\:g=\frac{5}{2}x+10\:\mathrm{substitute}\:x\:\mathrm{with}\:f\left(x\right)=\frac{2}{5}x-4\\\\=\frac{5}{2}\left(\frac{2}{5}x-4\right)+10\\\\=x$

so, both are inverses of each other.

c) Draw the graphs of f(x) and g(x) on the same coordinate plane.

As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x

And both f(x) and g(x) are symmetry to y=x.

∴ f(x) and g(x) are inverses of each other.

5 0

4 years ago