<h2>At 67 miles, cost of the two services is the same</h2><h3><u>Solution:</u></h3>
Given that,
<em><u>Delivery service A charges 10 for a pickup and 0.10 per mile</u></em>
Let "x" be the number of miles
Therefore,
Cost = 10 + 0.10(number of miles)
Cost = 10 + 0.10x ----- eqn 1
<em><u>Delivery service b charges 0.25 per mile </u></em>
Therefore,
Cost = 0.25(number of miles)
Cost = 0.25x ------ eqn 2
<em><u>At how many miles is the cost of the two services the same</u></em>
Eqn 1 = eqn 2
10 + 0.10x = 0.25x
0.25x - 0.10x = 10
0.15x = 10
Divide both sides by 0.15
Thus at 67 miles, cost of the two services is the same
